Does the weight of an engines rods effect horsepower output?
#51
The part to consider though is that the rod then has to be decelerated to stop and reverse which "returns" that energy. If you look at rod failures it has been determined, barring a contributing factor, that rods usually fail in tensile stress, essentially pulled apart, usually on the exhaust stroke, (decelerating) while "pulling" on the crankshaft.
#55
But we are still talking about rods that would be used in a Harley, ie we aren't talking about the difference in titanium and spent uranium rods... And the point I was making in that previous discussion is that energy used to accelerate the rod is still returned in deceleration of the rod, the energy is not gone. The question is vague anyway, since the answer could be based on ultimate peak power, rpm limited, unlimited, power at a given throttle setting or at WOT and specified rpm, or what happens, all other things the same, to the 1/4 mile time or dyno curves.
#56
But we are still talking about rods that would be used in a Harley, ie we aren't talking about the difference in titanium and spent uranium rods... And the point I was making in that previous discussion is that energy used to accelerate the rod is still returned in deceleration of the rod, the energy is not gone. The question is vague anyway, since the answer could be based on ultimate peak power, rpm limited, unlimited, power at a given throttle setting or at WOT and specified rpm, or what happens, all other things the same, to the 1/4 mile time or dyno curves.
You said that the energy expended when accelerating a rod is recovered when decelerating the rod. My response is that it is not recovered, but in fact takes another shot of energy to decelerate the rod.
Think of pushing a car from behind to get it rolling, and then pulling on it to stop it. Both require energy, and no energy is recovered. The energy is spent doing work, first accelerating the mass, and then stopping it.
#59
#60
so hang on minute Deuce, you say the guy added "forged rods" and why would he do that due to the greater weight of said rod. So are you hypothesizing the forged rod is heavier or do you know that as fact???? You need to add way more info to this question if you want an answer that is correct not only in the engineering world but correct for the application. Teflon