Load does NOT affect the psi in tires... 36 psi unloaded will still be 36 psi loaded... however the characteristics (shape, running temp, steering, etc.) of the tire will change.

 

Actually, the tire pressure will be higher with the bike on the ground instead of on the jack but I'd have to do the calculations to see if the increase is of any significance. Consider what happens when you step on a package of ketchup.

 

I think it's more important to check it routinely. Just check it the same way each time and keep it properly inflated.

 

What he said,just check when tire is cold.

 

Your average tire gauge isn't accurate enough to check your shocks with.

 

I realize we are directly discussing tires but someone mentioned shocks ... with the "air ride" Harley shocks DO NOT INFLATE WITH A COMPRESSOR.

The front suspension and rear shocks take precise low pressure to make them work and you will damage them using a standard compressor that will over inflate them and blow them out in seconds!!!!

Harley makes a small hand held pressure pump just for your suspension. They only require 10 psi, 15, maybe 20 at the most with a rider.

Don't "blow" your suspension using a standard compressor.

 

Actually, the internal psi will only rise if by stepping on it you reduce the size of the packet... otherwise the internal psi remains the same...the act alone of stepping on the packet does not increase the internal psi. Again, load does not affect the internal psi of any item. Item failure at critical mass is due to the alteration of other characteristics rather than a critical increase in internal psi.

 

P=FxA nuff said.....

 

tires are zero growth. this means they are limited to the amount they expand or they would rub the fenders and frame. This limits the pressure change whether on the ground or suspended to a minimum. ex. 36lbs either on or off the ground.
in argument, force does affect pressure, thats why my fat assed aunt can bust a balloon when she sits on it....

 

Actually the formula is P=F/A... Pressure = Normal Force divided by Area